Page No 159:
Question 5:
Is the function f defined by
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continuous at x = 0? At x = 1? At x = 2?
The given function f is ![]()
At x = 0,
It is evident that f is defined at 0 and its value at 0 is 0.
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Therefore, f is continuous at x = 0
At x = 1,
f is defined at 1 and its value at 1 is 1.
The left hand limit of f at x = 1 is,
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The right hand limit of f at x = 1 is,

Therefore, f is not continuous at x = 1
At x = 2,
f is defined at 2 and its value at 2 is 5.
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Therefore, f is continuous at x = 2