Page No 159:
Question 2:
If E, F, G and H are respectively the mid-points of the sides of a parallelogram ABCD show that
area of (EFGH) 
area of (ABCD)
Page No 160:
Question 6:
A farmer was having a field in the form of a parallelogram PQRS. She took any point A on RS and joined it to points P and Q. In how many parts the field is divided? What are the shapes of these parts? The farmer wants to sow wheat and pulses in equal portions of the field separately. How should she do it?
Page No 163:
Question 6:
In the given figure, diagonals AC and BD of quadrilateral ABCD intersect at O such that OB = OD. If AB = CD, then show that:
(i) ar (DOC) = ar (AOB)
(ii) ar (DCB) = ar (ACB)
(iii) DA || CB or ABCD is a parallelogram.
[Hint: From D and B, draw perpendiculars to AC.]
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Question 9:
The side AB of a parallelogram ABCD is produced to any point P. A line through A and parallel to CP meets CB produced at Q and then parallelogram PBQR is completed (see the following figure). Show that
ar (ABCD) = ar (PBQR).
[Hint: Join AC and PQ. Now compare area (ACQ) and area (APQ)]
Page No 164:
Question 13:
ABCD is a trapezium with AB || DC. A line parallel to AC intersects AB at X and BC at Y. Prove that area (ADX) = area (ACY).
[Hint: Join CX.]
