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Class 9
Maths :-NCERT Solutions - Polynomials

Page No 49:
Question 7:
Evaluate the following using suitable identities:
(i) (99)3 (ii) (102)3 (iii) (998)3

Answer:

It is known that,

(i) (99)= (100 − 1)3
= (100)3 − (1)3 − 3(100) (1) (100 − 1)
= 1000000 − 1 − 300(99)
= 1000000 − 1 − 29700
= 970299
(ii) (102)3 = (100 + 2)3
= (100)3 + (2)3 + 3(100) (2) (100 + 2)
= 1000000 + 8 + 600 (102)
= 1000000 + 8 + 61200
= 1061208
(iii) (998)3= (1000 − 2)3
= (1000)3 − (2)3 − 3(1000) (2) (1000 − 2)
= 1000000000 − 8 − 6000(998)
= 1000000000 − 8 − 5988000
= 1000000000 − 5988008
= 994011992