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Class 12
Maths :-NCERT Solutions - Linear Programming

Page No 513:

Question 1:
Maximise Z = 3x + 4y
Subject to the constraints:



Answer:

The feasible region determined by the constraints, x y ≤ 4, x ≥ 0, y ≥ 0, is as follows.

The corner points of the feasible region are O (0, 0), A (4, 0), and B (0, 4). The values of Z at these points are as follows.

Corner point

Z = 3x + 4y

O(0, 0)

0

A(4, 0)

12

B(0, 4)

16

→ Maximum 

Therefore, the maximum value of Z is 16 at the point B (0, 4).