It is given that *: P(X) × P(X) → P(X) is defined as
A * B = (A − B) ∪ (B − A) &mnForE; A, B ∈ P(X).
Let A ∈ P(X). Then, we have:
A * Φ = (A − Φ) ∪ (Φ − A) = A ∪ Φ = A
Φ * A = (Φ − A) ∪ (A − Φ) = Φ ∪ A = A
∴A * Φ = A = Φ * A. &mnForE; A ∈ P(X)
Thus, Φ is the identity element for the given operation*.
Now, an element A ∈ P(X) will be invertible if there exists B ∈ P(X) such that
A * B = Φ = B * A. (As Φ is the identity element)
Now, we observed that
.
Hence, all the elements A of P(X) are invertible with A−1 = A.
