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Question 14:
Let
be a function defined as
. The inverse of f is map g: Range![]()
(A)
(B) ![]()
(C)
(D) ![]()
It is given that![]()
Let y be an arbitrary element of Range f.
Then, there exists x ∈
such that ![]()

Let us define g: Range
as![]()
Now,![]()


∴![]()
Thus, g is the inverse of f i.e., f−1 = g.
Hence, the inverse of f is the map g: Range
, which is given by
![]()
The correct answer is B.