Page No 11:
Question 7:
In each of the following cases, state whether the function is one-one, onto or bijective. Justify your answer.
(i) f: R → R defined by f(x) = 3 − 4x
(ii) f: R → R defined by f(x) = 1 + x2
(i) f: R → R is defined as f(x) = 3 − 4x.
.
∴ f is one-one.
For any real number (y) in R, there exists
in R such that
∴f is onto.
Hence, f is bijective.
(ii) f: R → R is defined as
.
.
∴
does not imply that
For instance,
∴ f is not one-one.
Consider an element −2 in co-domain R.
It is seen thatis positive for all x ∈ R.
Thus, there does not exist any x in domain R such that f(x) = −2.
∴ f is not onto.
Hence, f is neither one-one nor onto.
