Exercise 2
Question 21
Gold (atomic radius = 0.144 nm) crystallises in a face-centred unit cell. What is the length of a side of the cell?
We know, for a fcc unit cell,radius of atom
r = a/2√2
Or
a = 2r√2
By putting the values of r &√2 we get
a = 2 x 0.144 x 1.414 = 0.407nm