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Class 12
Chemistry :-NCERT Solutions - The Solid State

Question 6
Classify the following solids in different categories based on the nature of intermolecular forces operating in them:
Potassium sulphate, tin, benzene, urea, ammonia, water, zinc sulphide, graphite, rubidium, argon, silicon carbide.


Answer:

Answer

Potassium sulphate → Ionic bond is formed,wherein potassium loses electrons & sulphate gains electrons

Tin → Tin can form two ions Sn 2+ or Sn4+ now depending on what form it is in and what other element it is bonding with then only the type of bonding will be known

Benzene → it is comprise of sp2 hybridized carbon atoms which makes covalent bond with each other by mutual sharing &pairing of electrons

Urea → Polar molecular solid & they mostly forms hydrogen bond with other atoms

Ammonia → covalently bonded  polar compound formed by mutual sharing & pairing of electrons between nitrogen & three hydrogen atoms

Water → covalently  bonded  polar compound formed by mutual sharing of electrons between oxygen & hydrogen atoms

Zinc sulphide → it exist in the form of crystals & makes coordination bond

Graphite → it consist of carbon atoms & have covalent bond between them forming a 2-D (flat, planar etc.) network, which in itself is strong. These planes are then held together by London Forces, which are very weak.

Rubidium → Metallic bond is formed by rubidium because it is a metal.Metallic bond is hydrid of covalent bond & ionic bond

Argon → Non-polar molecular solid

Silicon carbide → Covalent or network solid