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Class 11
Physics :-NCERT Solutions - SYSTEM OF PARTICLES AND ROTATIONAL MOTION

Page No 180:
Question 7.24:
A bullet of mass 10 g and speed 500 m/s is fired into a door and gets embedded exactly at the centre of the door. The door is 1.0 m wide and weighs 12 kg. It is hinged at one end and rotates about a vertical axis practically without friction. Find the angular speed of the door just after the bullet embeds into it.
(Hint: The moment of inertia of the door about the vertical axis at one end is ML2/3.)


Answer:

Mass of the bullet, m = 10 g = 10 × 10–3 kg

Velocity of the bullet, v = 500 m/s

Thickness of the door, L = 1 m

Radius of the door, r = 

Mass of the door, M = 12 kg

Angular momentum imparted by the bullet on the door:

α = mvr

Moment of inertia of the door:


SET

NCERT Physics Class 11